问题

在运行时输入一个句子，并编写一段代码来计算句子中出现的单词的平均长度

解决方案

START
Step 1: declare character, int and double variables
Step 2: Enter any statement
Step 3: while loop
       Check condition stmt[i]=getchar()) != '
'
       True then enter into loop
       Increment I and call the function at step 5
Step 4: Print the average length return by function
       From step 5
Step 5: called function calculatewordlength
         i. declare and initialize
            charcount=0 and wordcount=1
         ii. while loop
            check condition (*stmt != '
')
            if it trues enter into loop
            1.    if(*stmt != ' ')
            2.    charcount++;
            3.    else if(*stmt == ' ')
            4.    wordcount++;
            5.    stmt++;
         iii. return (double)charcount/wordcount;
STOP

程序

#include<stdio.h>
#include<string.h>
double calculatewordlength(const char *stmt);
int main(){
   char stmt[100];
   int i=0;
   double avglen;
   printf("enter any statement:");
   while((stmt[i]=getchar()) != '
')
      i++;
   stmt[i]='
';
   avglen=calculatewordlength(stmt);
   printf("average length of word is:%f.
 ", avglen);
}
double calculatewordlength(const char *stmt){
   int charcount=0;
   int wordcount=1;
   while(*stmt != '
'){
      if(*stmt != ' ')
         charcount++;
      else if(*stmt == ' ')
         wordcount++;
      stmt++;
   }
   return (double)charcount/wordcount;
}

输出

enter any statement:Tutorials Point is the best resource for online education average length of word: 5.444444444.